Matches 1 to 2 of 2 for First Name starts with SERENA AND Tree equals Robin
# | Last Name, Given Name(s) ![]() |
Person ID | Born ![]() |
Location | Tree | Branch |
---|---|---|---|---|---|
1 | ![]() | I20738 | b. 13 Feb 1874 | Bradley County, Tennessee, USA ![]() | rr-Robin |
2 | ![]() | I28958 | b. 17 Jun 1818 | Tennessee, USA ![]() | rr-Robin |